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CBSE NCERT Chapter Notes

Polynomials

Class 9 Mathematics, Chapter 2

By Preksha InstitutePublished: 23 October 202628 min readMediumExam relevant
Mathematics chapters2 of 15
  1. 01Number Systems
  2. 02Polynomials
  3. 03Coordinate Geometry
  4. 04Linear Equations in Two Variables
  5. 05Introduction to Euclids Geometry
  6. 06Lines and Angles
  7. 07Triangles
  8. 08Quadrilaterals
  9. 09Areas of Parallelograms and Triangles
  10. 10Circles
  11. 11Constructions
  12. 12Herons Formula
  13. 13Surface Areas and Volumes
  14. 14Statistics
  15. 15Probability
Class 9

Mathematics

Chapter 2 of 15

  1. 01Number Systems
  2. 02Polynomials
  3. 03Coordinate Geometry
  4. 04Linear Equations in Two Variables
  5. 05Introduction to Euclids Geometry
  6. 06Lines and Angles
  7. 07Triangles
  8. 08Quadrilaterals
  9. 09Areas of Parallelograms and Triangles
  10. 10Circles
  11. 11Constructions
  12. 12Herons Formula
  13. 13Surface Areas and Volumes
  14. 14Statistics
  15. 15Probability
View subject overview
Home›Resources›class 9›mathematics›polynomials
Quick Links:Resources HomeBack to Class 9View all chapters
Class 9MathematicsChapter 2Preksha • Concept Revision

Polynomials

Concept-first revision with intuition, formal rules, worked examples, exam reasoning and focused practice.

Chapter Snapshot

  • A polynomial is built from variables with non-negative integral powers.
  • The degree is the highest power with a non-zero coefficient.
  • A zero of p(x) is a value a for which p(a)=0.
  • The remainder when p(x) is divided by x-a is p(a).
  • x-a is a factor of p(x) exactly when p(a)=0.
  • Identities help both expansion and factorisation.

What You Will Learn

  • ✓Recognise polynomials in one variable and identify degree and coefficients
  • ✓Evaluate a polynomial at a given value
  • ✓Understand zeros of a polynomial
  • ✓Use the remainder theorem and factor theorem
  • ✓Factorise suitable polynomials
  • ✓Use algebraic identities confidently
Exam PriorityBoardsVery HighFoundationVery High

Why This Chapter Matters

Algebra becomes powerful when we stop treating expressions as strings of symbols and start seeing their structure. A polynomial is one of the simplest structured algebraic objects: terms are built from non-negative whole-number powers of a variable and then combined by addition or subtraction.

Why are polynomials important? They model patterns, areas, motion and equations. More importantly, they teach a central mathematical habit: evaluate, test, factor and reason from structure.

The chapter moves naturally from recognising polynomials to asking a deeper question: when does a polynomial become zero? That question leads to the remainder theorem, factor theorem and factorisation. The whole chapter is therefore a story about how a complicated expression reveals hidden factors when we test the right values.

Bridge from Earlier Classes

Before starting, be comfortable with:

  • Algebraic expressions
  • Like and unlike terms
  • Laws of exponents
  • Class 8 identities
  • Basic factorisation

These are the tools this chapter reuses and deepens.

1. What Counts as a Polynomial?

A polynomial in x contains terms such as 5x³, -2x and 7, where the exponents of x are non-negative integers.

Expressions such as 3/x, √x or x^-2 are not polynomials in x because they involve negative or fractional powers. The restriction on exponents is what gives polynomials their predictable algebraic behaviour.

The coefficient is the numerical factor of a term. A missing power can be thought of as having coefficient zero. For example, x³-5x+2 can be written as x³+0x²-5x+2.

2. Degree and Types

The degree of a non-zero polynomial is the highest exponent with a non-zero coefficient. A non-zero constant polynomial has degree 0, a linear polynomial degree 1, a quadratic degree 2 and a cubic degree 3.

The zero polynomial needs special care. Since every coefficient is zero, there is no highest power with a non-zero coefficient, so its degree is not assigned in the usual school definition.

3. Value and Zeros

To evaluate p(x) at x=a, substitute a everywhere x occurs. If p(a)=0, then a is called a zero of the polynomial.

For a linear polynomial ax+b, the zero is -b/a when a≠0. A zero is not a missing term or a zero coefficient. It is an input value that makes the entire polynomial equal to zero.

This distinction is crucial because zeros later become x-coordinates where graphs meet the x-axis and also create factors through the factor theorem.

4. Remainder Theorem

Suppose p(x) is divided by x-a. The remainder theorem says the remainder is p(a).

Why is this useful? Polynomial division can be long, while substitution is quick. If the divisor is x-3, evaluate p(3). If the divisor is x+2, rewrite it as x-(-2), so evaluate p(-2).

The theorem creates a bridge between division and evaluation. It is also the immediate foundation for the factor theorem.

5. Factor Theorem

The factor theorem is the zero-remainder case of the remainder theorem. If p(a)=0, dividing by x-a leaves remainder zero, so x-a is a factor. Conversely, if x-a is a factor, p(a)=0.

This suggests a systematic strategy for factorising higher-degree polynomials: test likely integer values, find a zero, remove the corresponding linear factor, then factor the remaining lower-degree expression.

6. Factorisation by Identities

Identities are algebraic relationships that hold for all permitted values. They are useful in both directions: expansion and factorisation.

Before applying an identity, look for structure. Are the first and last terms perfect squares? Is the middle term twice the product? Is the expression a difference of squares? Is there a common factor that should be taken out first?

A reliable routine is: common factor → identity pattern → factor theorem if needed.

7. Identities as Calculation Tools

Identities are not only examination formulas. They simplify numerical calculations as well. For example, 103² can be evaluated as (100+3)² instead of using long multiplication.

The deeper lesson is that symbolic algebra can make arithmetic more efficient by exposing structure.

Visualise the Core Idea

A polynomial becomes easier when you separate its structural parts.

Formula / Theorem Sheet

Formula / Key Relations

Remainder theorem

Remainder on division by (x−a)=p(a)\text{Remainder on division by }(x-a)=p(a)Remainder on division by (x−a)=p(a)

Use the value a exactly as written in x-a.

Factor theorem

p(a)=0  ⟺  (x−a) is a factor of p(x)p(a)=0\iff(x-a)\text{ is a factor of }p(x)p(a)=0⟺(x−a) is a factor of p(x)

A zero creates a linear factor.

Square of a sum

(a+b)2=a2+2ab+b2(a+b)^2=a^2+2ab+b^2(a+b)2=a2+2ab+b2

Expansion and factorisation.

Square of a difference

(a−b)2=a2−2ab+b2(a-b)^2=a^2-2ab+b^2(a−b)2=a2−2ab+b2

The last term remains positive.

Difference of squares

a2−b2=(a+b)(a−b)a^2-b^2=(a+b)(a-b)a2−b2=(a+b)(a−b)

Very common factorisation pattern.

Sum of cubes

a3+b3=(a+b)(a2−ab+b2)a^3+b^3=(a+b)(a^2-ab+b^2)a3+b3=(a+b)(a2−ab+b2)

Watch the signs.

Difference of cubes

a3−b3=(a−b)(a2+ab+b2)a^3-b^3=(a-b)(a^2+ab+b^2)a3−b3=(a−b)(a2+ab+b2)

Watch the signs.

Worked Examples — Follow the Reasoning

Degree and type
Question
Find the degree of 7 - 3x + 5x\u2074.
Solution

The highest non-zero power is 4.

So the degree is 4.

Remainder theorem
Question
Find the remainder when p(x)=x\u00b3-4x+1 is divided by x-2.
Solution
p(2)=23−4(2)+1p(2)=2^3-4(2)+1p(2)=23−4(2)+1=8−8+1=1=8-8+1=1=8−8+1=1

So the remainder is 1.

Factor theorem
Question
Show that x-2 is a factor of x\u00b2-5x+6.
Solution
p(2)=22−5(2)+6=0p(2)=2^2-5(2)+6=0p(2)=22−5(2)+6=0

Therefore x-2 is a factor.

Factorisation
Question
Factorise x\u00b2+7x+12.
Solution

Find two numbers with sum 7 and product 12: 3 and 4.

x2+7x+12=(x+3)(x+4)x^2+7x+12=(x+3)(x+4)x2+7x+12=(x+3)(x+4)

How to Think in the Exam

Exam Point:

Identify degree and structure before calculating. For factor questions, take common factors first, test likely zeros when needed, and use identities only when the pattern really matches.

Common Mistakes

Common Mistake

Mistake: Calling 1/x a polynomial term.

Correct idea: It is x^-1, so the exponent is negative.

Common Mistake

Mistake: For divisor x+3, evaluating p(3).

Correct idea: x+3 = x-(-3), so evaluate p(-3).

Common Mistake

Mistake: Thinking a zero of a polynomial means its constant term is zero.

Correct idea: A zero is an input value a for which p(a)=0.

Key Terms

PolynomialTermCoefficientDegreeConstant PolynomialZero of a PolynomialRemainder TheoremFactor TheoremIdentity

Quick Revision

Quick Revision

  • A polynomial is built from variables with non-negative integral powers.
  • The degree is the highest power with a non-zero coefficient.
  • A zero of p(x) is a value a for which p(a)=0.
  • The remainder when p(x) is divided by x-a is p(a).
  • x-a is a factor of p(x) exactly when p(a)=0.
  • Identities help both expansion and factorisation.
  • Revise the reasoning behind each rule once, not only the final formula.

Focused Practice

Q1MCQModerateClass 9

Degree of 5x³ - 2x + 9?

View Solution

3

Q2Short AnswerModerateClass 9

Find p(-1) for p(x)=x²+2x+3.

View Solution

2

Q3Short AnswerModerateClass 9

Find the remainder when x²+1 is divided by x-1.

View Solution

2

Q4NumericalModerateClass 9

Check whether x+2 is a factor of x³+3x²-4.

View Solution

Yes, because p(-2)=0.

Q5HOTSModerateClass 9

Can a non-zero constant polynomial have a zero?

View Solution

No. Its value is the same non-zero constant for every input.

Q6Long AnswerModerateClass 9

Explain how the remainder theorem leads to the factor theorem.

View Solution

If p(a) is the remainder on division by x-a, then p(a)=0 means remainder zero, exactly the condition for x-a to divide p(x) completely.

Final Chapter Summary

Chapter Summary

  • A polynomial is built from variables with non-negative integral powers.
  • The degree is the highest power with a non-zero coefficient.
  • A zero of p(x) is a value a for which p(a)=0.
  • The remainder when p(x) is divided by x-a is p(a).
  • x-a is a factor of p(x) exactly when p(a)=0.
  • Identities help both expansion and factorisation.
  • Strong revision means understanding why the method works, then practising enough examples to recognise when to use it.

Related Chapters

Number Systems
Coordinate Geometry
Previous chapterNumber SystemsNext chapterCoordinate Geometry
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