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CBSE NCERT Chapter Notes

Motion

Class 9 Science, Chapter 8

By Preksha InstitutePublished: 23 October 202632 min readMediumExam relevant
Science chapters8 of 15
  1. 01Matter in Our Surroundings
  2. 02Is Matter Around Us Pure
  3. 03Atoms and Molecules
  4. 04Structure of the Atom
  5. 05The Fundamental Unit of Life
  6. 06Tissues
  7. 07Diversity in Living Organisms
  8. 08Motion
  9. 09Force and Laws of Motion
  10. 10Gravitation
  11. 11Work and Energy
  12. 12Sound
  13. 13Why Do We Fall Ill
  14. 14Natural Resources
  15. 15Improvement in Food Resources
Class 9

Science

Chapter 8 of 15

  1. 01Matter in Our Surroundings
  2. 02Is Matter Around Us Pure
  3. 03Atoms and Molecules
  4. 04Structure of the Atom
  5. 05The Fundamental Unit of Life
  6. 06Tissues
  7. 07Diversity in Living Organisms
  8. 08Motion
  9. 09Force and Laws of Motion
  10. 10Gravitation
  11. 11Work and Energy
  12. 12Sound
  13. 13Why Do We Fall Ill
  14. 14Natural Resources
  15. 15Improvement in Food Resources
View subject overview
Home›Resources›class 9›science›motion
Quick Links:Resources HomeBack to Class 9View all chapters
Class 9ScienceChapter 8Preksha • Deep Concept Revision

Motion

Concept-first revision with scientific reasoning, everyday links, diagrams, worked examples and exam-focused practice.

Chapter Snapshot

  • Motion is described relative to a reference point or frame.
  • Distance is total path length; displacement is directed change from initial to final position.
  • Speed is rate of distance; velocity is rate of displacement.
  • Acceleration is rate of change of velocity.
  • For uniform acceleration, v=u+at, s=ut+½at² and v²-u²=2as.
  • Constant speed in a circle still involves acceleration because velocity direction changes.

What You Will Learn

  • ✓Distinguish distance from displacement and speed from velocity
  • ✓Calculate average speed and velocity
  • ✓Explain acceleration
  • ✓Interpret distance-time and velocity-time graphs
  • ✓Use equations of uniformly accelerated motion
  • ✓Explain uniform circular motion as accelerated motion
Exam PriorityBoardsVery HighFoundationVery High

Why This Chapter Matters

A car moving at 60 km/h is not fully described until we know direction and reference. Motion becomes precise only when position is measured relative to something. The chapter develops that description step by step: distance becomes displacement when direction matters, speed becomes velocity when direction matters, and changing velocity becomes acceleration. Graphs and equations are simply two different languages for the same motion story.

Bridge from Earlier Learning

  • Units of length and time
  • Simple ratios
  • Coordinate graphs
  • Basic algebra

These ideas are reused and deepened in this chapter.

1. Reference and Position

Start with the Core Idea

Whether an object is at rest or in motion depends on the chosen reference. A passenger is at rest relative to a train seat but moving relative to the ground. Scientific descriptions therefore specify a frame or reference point and track position relative to it.

2. Distance and Displacement

Distance is total path length and is always non-negative. Displacement is the directed change from initial to final position. Its magnitude cannot exceed distance and can be zero after non-zero travel. Walking 100 m east and 100 m west gives distance 200 m but displacement zero.

3. Speed and Velocity

Speed is distance per unit time. Velocity is displacement per unit time with direction. Average speed uses total distance divided by total time; average velocity uses total displacement divided by total time. An object can keep constant speed while changing velocity if its direction changes.

4. Acceleration

Acceleration measures rate of change of velocity. It can result from change in speed, direction or both. Negative acceleration is often called retardation in school problems, but the sign depends on the chosen positive direction. Always establish a sign convention before substitution.

5. Distance-Time Graphs

A distance-time graph shows how distance changes with time. Constant slope means uniform speed; a steeper line means greater speed. A horizontal segment means distance is not changing. Curved graphs indicate changing speed. The slope therefore converts a picture into a rate.

6. Velocity-Time Graphs

The slope of a velocity-time graph gives acceleration. For uniform acceleration the graph is a straight line. The area under the graph gives displacement because velocity multiplied by time has dimensions of distance. This graph also gives a geometric route to equations of motion.

7. Equations of Uniformly Accelerated Motion

When acceleration is constant, three equations connect initial velocity u, final velocity v, acceleration a, time t and displacement s. Choose the equation containing the known quantities and one required unknown. These equations should not be applied blindly to varying acceleration.

8. Uniform Circular Motion

In uniform circular motion, speed stays constant but direction changes continuously. Since velocity includes direction, velocity changes and the object is accelerated toward the centre. This is a key example showing that acceleration does not simply mean speeding up.

Compare the Ideas

Distance vs Displacement

FeatureDistanceDisplacement
MeaningTotal path lengthDirected change in position
TypeScalarVector
Can be zero after motion?NoYes
Relation≥ displacement magnitude≤ distance

Visualise the Concept

Graphs turn motion into slope and area relationships.

Formula / Relationship Sheet

Formula / Key Relations

Speed

speed=distancetime\text{speed}=\frac{\text{distance}}{\text{time}}speed=timedistance​

Scalar path rate.

Velocity

v⃗=displacementtime\vec v=\frac{\text{displacement}}{\text{time}}v=timedisplacement​

Direction matters.

Acceleration

a=v−uta=\frac{v-u}{t}a=tv−u​

Change in velocity per time.

First equation

v=u+atv=u+atv=u+at

Constant acceleration.

Second equation

s=ut+12at2s=ut+\frac12at^2s=ut+21​at2

Constant acceleration.

Third equation

v2−u2=2asv^2-u^2=2asv2−u2=2as

Useful when time is not needed.

Worked Examples & Scientific Reasoning

Average speed
Question
A car travels 120 km in 2 h.
Solution
v=1202=60 km h−1v=\frac{120}{2}=60\text{ km h}^{-1}v=2120​=60 km h−1
Acceleration
Question
Velocity changes from 5 m/s to 15 m/s in 4 s.
Solution
a=15−54=2.5 m s−2a=\frac{15-5}{4}=2.5\text{ m s}^{-2}a=415−5​=2.5 m s−2
Equation of motion
Question
A body starts from rest and accelerates at 2 m/s\u00b2 for 5 s. Find displacement.
Solution

u=0, a=2 m/s², t=5 s.

s=ut+12at2=25 ms=ut+\frac12at^2=25\text{ m}s=ut+21​at2=25 m
Circular motion
Question
Why is circular motion accelerated at constant speed?
Solution

Velocity direction changes continuously.

Observe Like a Scientist

Create a Motion Graph

Aim

Use a simple observation to test or visualise the central idea.

Method

Walk a measured straight path at nearly steady pace while a partner records position every few seconds. Plot position against time. Repeat with a deliberate pause and compare the graph.

What to Record

Write what you observe first, then explain it using the chapter concept.

Exam Thinking Strategy

Exam Point:

Define the reference and positive direction, list known variables with units, then choose the graph or equation that directly connects them.

Common Mistakes

Common Mistake

Mistake: Distance and displacement are always equal.

Correct idea: They are equal only in special straight-line motion without reversal.

Common Mistake

Mistake: Zero acceleration means zero velocity.

Correct idea: It means velocity is constant; the object may still be moving.

Common Mistake

Mistake: Constant speed means constant velocity.

Correct idea: Velocity changes if direction changes.

Key Terms

Reference FrameDistanceDisplacementSpeedVelocityAccelerationUniform MotionEquation of MotionUniform Circular Motion

Quick Revision

Quick Revision

  • Motion is described relative to a reference point or frame.
  • Distance is total path length; displacement is directed change from initial to final position.
  • Speed is rate of distance; velocity is rate of displacement.
  • Acceleration is rate of change of velocity.
  • For uniform acceleration, v=u+at, s=ut+½at² and v²-u²=2as.
  • Constant speed in a circle still involves acceleration because velocity direction changes.
  • Revise the explanation behind each definition or formula, not only the wording.

Focused Practice

Q1MCQModerateClass 9

Slope of a velocity-time graph gives?

View Solution

Acceleration

Q2ShortModerateClass 9

A runner completes one full circular lap. What is displacement?

View Solution

Zero.

Q3NumericalModerateClass 9

Velocity changes from 10 m/s to 22 m/s in 6 s. Find acceleration.

View Solution

2 m/s²

Q4NumericalModerateClass 9

u=5 m/s, a=3 m/s², t=4 s. Find v.

View Solution

17 m/s

Q5HOTSModerateClass 9

Can an object have zero velocity and non-zero acceleration at an instant?

View Solution

Yes, for example at the highest point of a vertical throw while gravity still acts.

Q6Long AnswerModerateClass 9

Explain how distance-time and velocity-time graphs encode motion differently.

View Solution

Distance-time slope gives speed; velocity-time slope gives acceleration and area gives displacement.

Final Chapter Summary

Chapter Summary

  • Motion is described relative to a reference point or frame.
  • Distance is total path length; displacement is directed change from initial to final position.
  • Speed is rate of distance; velocity is rate of displacement.
  • Acceleration is rate of change of velocity.
  • For uniform acceleration, v=u+at, s=ut+½at² and v²-u²=2as.
  • Constant speed in a circle still involves acceleration because velocity direction changes.
  • A strong answer explains the mechanism or reason, then uses the correct scientific term, relation or example.

Related Chapters

Diversity in Living Organisms
Force and Laws of Motion
Previous chapterDiversity in Living OrganismsNext chapterForce and Laws of Motion
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