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CBSE NCERT Chapter Notes

Measurement of Time and Motion

Class 7 Science, Chapter 8

By Preksha InstitutePublished: 20 August 202636 min readMedium📋 Exam Relevant
Science chapters8 of 12
  1. 01The Ever-Evolving World of Science
  2. 02Exploring Substances: Acidic, Basic and Neutral
  3. 03Electricity: Circuits and Their Components
  4. 04The World of Metals and Non-metals
  5. 05Changes Around Us: Physical and Chemical
  6. 06Adolescence: A Stage of Growth and Change
  7. 07Heat Transfer in Nature
  8. 08Measurement of Time and Motion
  9. 09Life Processes in Animals
  10. 10Life Processes in Plants
  11. 11Light: Shadows and Reflections
  12. 12Earth, Moon and the Sun
Class 7

Science

Chapter 8 of 12

  1. 01The Ever-Evolving World of Science
  2. 02Exploring Substances: Acidic, Basic and Neutral
  3. 03Electricity: Circuits and Their Components
  4. 04The World of Metals and Non-metals
  5. 05Changes Around Us: Physical and Chemical
  6. 06Adolescence: A Stage of Growth and Change
  7. 07Heat Transfer in Nature
  8. 08Measurement of Time and Motion
  9. 09Life Processes in Animals
  10. 10Life Processes in Plants
  11. 11Light: Shadows and Reflections
  12. 12Earth, Moon and the Sun
View subject overview
Home›Resources›class 7›science›measurement of time and motion
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Class 7ScienceChapter 8NCERT • Curiosity

Measurement of Time and Motion

Learn how time is measured, investigate the motion of a simple pendulum, calculate speed, and distinguish between uniform and non-uniform linear motion.

Chapter Snapshot

  • Regularly repeating events have been used to measure time since ancient times.
  • The SI unit of time is the second, written as s.
  • Clocks, watches and stopwatches provide convenient ways of measuring time.
  • A simple pendulum consists of a small bob suspended from a fixed support by a light string.
  • One complete to-and-fro motion of a pendulum is called an oscillation.
  • The time required for one complete oscillation is called the time period.
  • An object is in motion when its position changes with time relative to a reference point.
  • Speed tells us how much distance an object travels per unit time.
  • The SI unit of speed is metre per second, written as m/s.
  • In uniform linear motion, equal distances are covered in equal intervals of time.
  • In non-uniform linear motion, unequal distances are covered in equal intervals of time.

What You Will Learn

  • ✓Explain why measurement of time is important in everyday life
  • ✓Describe traditional and modern methods of measuring time
  • ✓State the SI unit of time and convert between common time units
  • ✓Identify the main parts of a simple pendulum
  • ✓Define oscillation and time period of a pendulum
  • ✓Measure the time period of a simple pendulum experimentally
  • ✓Explain motion using the idea of a reference point
  • ✓Compare the speeds of moving objects
  • ✓Calculate speed using distance and time
  • ✓Calculate distance or time when other quantities are known
  • ✓Distinguish between uniform and non-uniform linear motion
  • ✓Interpret simple motion tables and distance-time representations
Exam PriorityBoardsVery HighFoundationVery High

Chapter Overview

Imagine watching a 100-metre race.

Two runners cross the finish line almost together. How can we decide who won?

We need to measure the time taken by each runner accurately.

Now imagine two vehicles travelling on a road. One covers a much greater distance than the other in the same amount of time.

How can we compare how fast they are moving?

We need the concept of speed.

Measurement makes words such as "quick", "slow", "long time" and "short time" scientifically meaningful.

This chapter connects two important ideas:

  • measurement of time;
  • description of motion.

The Central Idea

Motion is described using measurable quantities.

Two of the most important are:

  • distance travelled;
  • time taken.

Together they allow us to calculate speed.

Speed=Distance travelledTime taken\text{Speed}=\frac{\text{Distance travelled}}{\text{Time taken}}Speed=Time takenDistance travelled​

Detailed Explanation

1. Why Do We Need to Measure Time?

We use time measurement throughout the day.

Examples include:

  • waking up for school;
  • timing a race;
  • knowing the duration of a class;
  • planning a journey;
  • cooking food;
  • measuring a scientific experiment;
  • scheduling trains and flights;
  • comparing sporting performances.

Without standard measurement, one person's idea of a "short time" may be very different from another person's.

Scientific measurement therefore requires:

  • a standard unit;
  • a reliable measuring device;
  • careful observation.

Measurement Makes Comparison Possible

Suppose Runner A says:

"I completed the race quickly."

Runner B says:

"I was also quick."

This does not tell us who was faster.

If their measured times are:

  • Runner A: 13.2 s
  • Runner B: 13.8 s

we can compare their performances objectively.

2. How Did People Measure Time in the Past?

Modern watches and clocks were not always available.

People observed natural events that repeated regularly.

Examples include:

  • sunrise and sunset;
  • phases of the Moon;
  • seasonal changes;
  • movement of shadows.

These repeating patterns helped people estimate longer periods of time.

Natural measures of time

A day is related to the rotation of the Earth.

A year is related to the revolution of the Earth around the Sun.

Months were historically connected with repeating changes in the appearance of the Moon.

Natural events, however, are not convenient for measuring short intervals such as:

  • a few seconds;
  • the duration of a race;
  • the time taken for an experiment.

People therefore developed different time-measuring devices.

3. Traditional Time-Measuring Devices

Sundial

A sundial uses the changing position of a shadow produced by sunlight.

Sundial

A sundial is a device that estimates time using the changing position of a shadow formed by sunlight.

A major limitation is that it requires suitable sunlight.

Water Clock

Water clocks were designed so that water flowed at a controlled rate.

The amount of water collected or lost could be used to estimate elapsed time.

Sand Clock

A sand clock, or hourglass, contains two chambers joined by a narrow opening.

Sand flows gradually from one chamber to the other.

These traditional devices demonstrate an important principle:

A regularly repeating or sufficiently steady process can be used to measure time.

Diagram comparing a sundial, water clock and sand clock as traditional devices used for measuring time
Traditional time-measuring devices used natural or controlled repeating processes.

Did You Know?

Different civilisations developed their own methods of measuring time.

The development of clocks shows how scientific measurement became increasingly standardised and precise.

4. Modern Measurement of Time

Today we commonly use:

  • wall clocks;
  • wristwatches;
  • digital clocks;
  • mobile phones;
  • stopwatches;
  • electronic timers.

A stopwatch is especially useful for measuring short time intervals.

Stopwatch

A stopwatch is a device used to measure the time interval between a starting event and a stopping event.

Modern sporting competitions may use electronic timing because even a fraction of a second can affect the result.

Exam Point:

Use an ordinary clock for general timekeeping.

Use a stopwatch or timer when measuring short experimental or sporting time intervals.

5. Units of Time

Scientific measurements require standard units.

SI Unit of Time

The SI unit of time is the second.

Its symbol is s.

Common larger units are:

  • minute;
  • hour;
  • day.

Time Conversions

1 min=60 s1\text{ min}=60\text{ s}1 min=60 s1 h=60 min1\text{ h}=60\text{ min}1 h=60 min

Therefore:

1 h=3600 s1\text{ h}=3600\text{ s}1 h=3600 s

and:

1 day=24 h1\text{ day}=24\text{ h}1 day=24 h
Convert Minutes into Seconds
Question
Convert 5 minutes into seconds.
Solution

We know:

1 min=60 s1\text{ min}=60\text{ s}1 min=60 s

Therefore:

5 min=5×60 s5\text{ min}=5\times60\text{ s}5 min=5×60 s5 min=300 s5\text{ min}=300\text{ s}5 min=300 s

Thus:

300 s\boxed{300\text{ s}}300 s​
Convert Hours into Minutes
Question
Convert 2.5 hours into minutes.
Solution

We know:

1 h=60 min1\text{ h}=60\text{ min}1 h=60 min

Therefore:

2.5 h=2.5×60 min2.5\text{ h}=2.5\times60\text{ min}2.5 h=2.5×60 min2.5 h=150 min2.5\text{ h}=150\text{ min}2.5 h=150 min

Thus:

150 min\boxed{150\text{ min}}150 min​
Quick Check
How many seconds are there in 3 minutes?
Show answer
There are 180 seconds because 3 × 60 = 180.

6. Periodic Motion

A movement that repeats itself after equal intervals of time can be useful for measuring time.

One important example is a swinging pendulum.

Periodic Motion

A motion that repeats itself after equal intervals of time is called periodic motion.

Examples include:

  • repeated oscillation of a pendulum under suitable conditions;
  • regular vibration of certain objects;
  • repetitive motion used in some clocks.

7. The Simple Pendulum

A simple pendulum can be made using:

  • a small heavy object called a bob;
  • a light string;
  • a fixed support.

Simple Pendulum

A simple pendulum consists of a small bob suspended from a fixed support by a light string so that it can swing freely to and fro.

Labelled diagram of a simple pendulum showing fixed support, string, bob, mean position and extreme positions
A simple pendulum consists of a bob suspended from a fixed support by a string.

Mean Position

When the pendulum hangs freely at rest, the bob occupies its central position.

This is called the mean position.

Extreme Positions

When the bob swings, it reaches the farthest point on each side before reversing direction.

These are called the extreme positions.

Suppose:

  • O = mean position;
  • A = one extreme position;
  • B = the other extreme position.

One complete to-and-fro motion can be represented as:

A→O→B→O→AA\rightarrow O\rightarrow B\rightarrow O\rightarrow AA→O→B→O→A

One Oscillation

One complete to-and-fro motion of a pendulum from one extreme position to the other and back to the starting extreme position is called one oscillation.

Common Mistake

Mistake: Motion from one extreme position to the other is one complete oscillation.

Correct idea: Motion from one extreme position to the other represents only half of the complete to-and-fro motion.

The bob must return to its starting extreme position to complete one oscillation.

8. Time Period of a Pendulum

The time taken by a pendulum to complete one oscillation is called its time period.

Time Period

The time period of a simple pendulum is the time taken by the pendulum to complete one full oscillation.

If the total time for several oscillations is measured, the time period can be calculated.

Time Period of a Pendulum

T=tNT=\frac{t}{N}T=Nt​

where:

  • T = time period of one oscillation;
  • t = total measured time;
  • N = number of complete oscillations.

The SI unit of time period is the second (s).

Find the Time Period
Question
A pendulum completes 20 oscillations in 40 seconds. Find its time period.
Solution

Given

N=20N=20N=20t=40 st=40\text{ s}t=40 s

Formula

T=tNT=\frac{t}{N}T=Nt​

Substitution

T=4020T=\frac{40}{20}T=2040​

Calculation

T=2 sT=2\text{ s}T=2 s

Therefore:

T=2 s\boxed{T=2\text{ s}}T=2 s​

Measure the Time Period of a Simple Pendulum

Aim

To measure the time period of a simple pendulum.

Materials

  • small bob;
  • thread;
  • fixed support;
  • stopwatch.

Procedure

  1. Tie the bob securely to the thread.
  2. Suspend the thread from a fixed support.
  3. Allow the bob to come to rest.
  4. Pull the bob slightly to one side.
  5. Release it gently without pushing.
  6. Choose a reference position for counting.
  7. Start the stopwatch.
  8. Count 20 complete oscillations.
  9. Stop the stopwatch after the twentieth oscillation.
  10. Record the total time.
  11. Repeat the experiment two or three times.

Calculation

If t is the total time for N oscillations:

T=tNT=\frac{t}{N}T=Nt​

Why measure many oscillations?

Measuring only one oscillation can produce a relatively large error because starting and stopping a stopwatch at exactly the correct instant is difficult.

Timing several oscillations and dividing by their number gives a more reliable estimate.

Improve Experimental Accuracy

Instead of timing only one oscillation:

Measure 20 oscillations → divide the total time by 20

Repeated measurements can further improve reliability.

Exam Tip

For pendulum numericals, remember:

T=Total timeNumber of oscillationsT=\frac{\text{Total time}}{\text{Number of oscillations}}T=Number of oscillationsTotal time​

Always count complete oscillations.

Quick Check
A pendulum completes 30 oscillations in 60 seconds. What is its time period?
Show answer
The time period is 2 seconds because 60 ÷ 30 = 2.

9. What Is Motion?

We see motion everywhere:

  • birds fly;
  • cars move;
  • people walk;
  • a ball rolls;
  • leaves fall;
  • trains move along tracks;
  • planets move around the Sun.

But what exactly do we mean by motion?

Motion

An object is said to be in motion when its position changes with time relative to a chosen reference point.

The phrase reference point is important.

A student sitting inside a moving bus is:

  • at rest relative to the seat;
  • moving relative to a tree beside the road.

Thus, motion must be described relative to something.

Motion Is Relative

The same object may be:

  • stationary relative to one reference point;
  • moving relative to another.

Therefore, always ask:

Moving relative to what?

10. Linear Motion

An object moving along a straight path shows linear motion.

Linear Motion

Motion along a straight-line path is called linear motion.

Examples include:

  • a car travelling along a straight road;
  • a sprinter running on a straight track;
  • a lift moving vertically;
  • an object falling vertically.
Diagram showing an object moving through successive positions along a straight path
In linear motion, an object moves along a straight-line path.

11. Slow and Fast Motion

Suppose two students cover the same distance.

Student A takes 20 seconds.

Student B takes 15 seconds.

Student B is faster because the same distance was covered in less time.

Now suppose both move for 10 seconds.

Student A covers 40 metres.

Student B covers 60 metres.

Student B is again faster because a greater distance was covered in the same time.

This leads to the idea of speed.

12. Speed

Speed

Speed is the distance travelled by an object per unit time.

Speed Formula

Speed=Distance travelledTime taken\text{Speed}=\frac{\text{Distance travelled}}{\text{Time taken}}Speed=Time takenDistance travelled​

Using symbols:

v=dtv=\frac{d}{t}v=td​

where:

  • v = speed;
  • d = distance travelled;
  • t = time taken.

SI Unit of Speed

The SI unit of distance is metre.

The SI unit of time is second.

Therefore:

SI unit of speed=metresecond\text{SI unit of speed}=\frac{\text{metre}}{\text{second}}SI unit of speed=secondmetre​

Hence:

m/s\boxed{\text{m/s}}m/s​

It may also be written as:

m s−1\text{m s}^{-1}m s−1

Always Include Units

Writing only:

v = 5

is incomplete.

Write:

v=5 m/s\boxed{v=5\text{ m/s}}v=5 m/s​

A measured physical quantity should be expressed with an appropriate unit.

13. Calculating Speed

Speed of a Runner
Question
A runner covers 100 metres in 20 seconds. Calculate the speed.
Solution

Given

d=100 md=100\text{ m}d=100 mt=20 st=20\text{ s}t=20 s

Formula

v=dtv=\frac{d}{t}v=td​

Substitution

v=10020v=\frac{100}{20}v=20100​

Calculation

v=5 m/sv=5\text{ m/s}v=5 m/s

Therefore:

v=5 m/s\boxed{v=5\text{ m/s}}v=5 m/s​
Speed of a Car
Question
A car travels 150 metres in 10 seconds. Calculate its speed.
Solution

Given

d=150 md=150\text{ m}d=150 mt=10 st=10\text{ s}t=10 s

Formula

v=dtv=\frac{d}{t}v=td​

Substitution

v=15010v=\frac{150}{10}v=10150​

Calculation

v=15 m/sv=15\text{ m/s}v=15 m/s

Therefore:

15 m/s\boxed{15\text{ m/s}}15 m/s​
Quick Check
A cyclist travels 120 metres in 30 seconds. What is the speed?
Show answer
The speed is 4 m/s because 120 ÷ 30 = 4.

14. Calculating Distance

The speed formula can be rearranged to find distance.

From:

v=dtv=\frac{d}{t}v=td​

we obtain:

Distance Formula

d=vtd=vtd=vt

where:

  • d = distance;
  • v = speed;
  • t = time.
Find the Distance
Question
A cyclist moves at 6 m/s for 20 seconds. How far does the cyclist travel?
Solution

Given

v=6 m/sv=6\text{ m/s}v=6 m/st=20 st=20\text{ s}t=20 s

Formula

d=vtd=vtd=vt

Substitution

d=6×20d=6\times20d=6×20

Calculation

d=120 md=120\text{ m}d=120 m

Therefore:

120 m\boxed{120\text{ m}}120 m​

15. Calculating Time

From the speed formula:

v=dtv=\frac{d}{t}v=td​

time can be calculated using:

Time Formula

t=dvt=\frac{d}{v}t=vd​

where:

  • t = time;
  • d = distance;
  • v = speed.
Find the Time
Question
A runner travels 200 metres at a speed of 5 m/s. Find the time taken.
Solution

Given

d=200 md=200\text{ m}d=200 mv=5 m/sv=5\text{ m/s}v=5 m/s

Formula

t=dvt=\frac{d}{v}t=vd​

Substitution

t=2005t=\frac{200}{5}t=5200​

Calculation

t=40 st=40\text{ s}t=40 s

Therefore:

40 s\boxed{40\text{ s}}40 s​

16. Common Units of Speed

Speed may be expressed in:

  • metres per second;
  • kilometres per hour.

For scientific calculations, the SI unit is:

m/s\text{m/s}m/s

A vehicle's speedometer commonly displays:

km/h\text{km/h}km/h

Speedometer

A speedometer is an instrument in a vehicle that indicates its speed.

Odometer

An odometer is an instrument that records the distance travelled by a vehicle.

Vehicle dashboard diagram showing a speedometer indicating speed and an odometer recording distance travelled
A speedometer measures speed, while an odometer records distance travelled.

Speedometer vs Odometer

FeatureSpeedometerOdometer
MeasuresSpeedDistance travelled
Common unitkm/hkm
PurposeShows how fast a vehicle is movingRecords how far a vehicle has travelled

Common Mistake

Mistake: A speedometer measures distance travelled.

Correct idea: A speedometer measures speed, while an odometer records distance travelled.

17. Comparing Speeds Correctly

Suppose:

  • Car A covers 100 km in 2 h;
  • Car B covers 150 km in 3 h.

We should not decide that Car B is faster merely because it travelled farther.

Car A

vA=1002=50 km/hv_A=\frac{100}{2}=50\text{ km/h}vA​=2100​=50 km/h

Car B

vB=1503=50 km/hv_B=\frac{150}{3}=50\text{ km/h}vB​=3150​=50 km/h

Therefore:

vA=vBv_A=v_BvA​=vB​

Both have the same average speed over the journeys.

Distance Alone Does Not Tell Speed

To compare moving objects correctly, consider both distance and time.

Greater distance does not automatically mean greater speed.

Similarly, shorter time alone does not prove greater speed unless the distances are also considered.

18. Uniform Linear Motion

Suppose a toy car covers:

  • 5 m during the first second;
  • 5 m during the second second;
  • 5 m during the third second;
  • 5 m during the fourth second.

It covers equal distances in equal intervals of time.

Uniform Linear Motion

An object has uniform linear motion when it moves along a straight line and covers equal distances in equal intervals of time.

Example:

| Time Interval | Distance Covered | | ------------- | ---------------: | | 0–1 s | 5 m | | 1–2 s | 5 m | | 2–3 s | 5 m | | 3–4 s | 5 m |

Its speed remains constant.

Straight path showing an object at equally spaced positions after equal time intervals
In uniform linear motion, equal distances are covered in equal intervals of time.

19. Non-uniform Linear Motion

Consider a car moving through traffic.

During successive 10-second intervals it may travel:

  • 80 m;
  • 50 m;
  • 20 m;
  • 70 m.

The distances are different even though the time intervals are equal.

Non-uniform Linear Motion

An object has non-uniform linear motion when it moves along a straight path but covers unequal distances in equal intervals of time.

Its speed changes during the motion.

Examples include:

  • a bus moving through traffic;
  • a bicycle starting from rest and speeding up;
  • a vehicle slowing near a traffic signal;
  • a runner changing pace.
Straight path showing an object at unequal spacings after equal time intervals
In non-uniform linear motion, unequal distances are covered in equal intervals of time.

Uniform vs Non-uniform Linear Motion

FeatureUniform Linear MotionNon-uniform Linear Motion
PathStraight lineStraight line
Equal time intervalsEqual distances are coveredUnequal distances are covered
SpeedConstantChanges
ExampleObject moving steadily along a straight pathVehicle speeding up or slowing down
Quick Check
A car travels 10 m, 10 m, 10 m and 10 m during four successive one-second intervals along a straight road. What type of motion is this?
Show answer
It is uniform linear motion because equal distances are covered in equal time intervals.

20. Average Speed

Most real journeys are not perfectly uniform.

A bus may:

  • start slowly;
  • speed up;
  • stop at a bus stop;
  • slow near a junction;
  • travel faster on an open road.

For the complete journey, we can calculate average speed.

Average Speed

Average speed=Total distance travelledTotal time taken\text{Average speed}=\frac{\text{Total distance travelled}}{\text{Total time taken}}Average speed=Total time takenTotal distance travelled​
Average Speed of a Journey
Question
A bus travels 120 km in 3 hours. Find its average speed.
Solution

Given

d=120 kmd=120\text{ km}d=120 kmt=3 ht=3\text{ h}t=3 h

Formula

vavg=dtv_{\text{avg}}=\frac{d}{t}vavg​=td​

Substitution

vavg=1203v_{\text{avg}}=\frac{120}{3}vavg​=3120​

Calculation

vavg=40 km/hv_{\text{avg}}=40\text{ km/h}vavg​=40 km/h

Therefore:

40 km/h\boxed{40\text{ km/h}}40 km/h​

This does not mean that the bus moved at exactly 40 km/h at every moment.

Average Speed Is an Overall Measure

For non-uniform motion, average speed does not describe the exact speed at every moment.

It compares:

total distance travelled

with:

total time taken

for the complete journey.

21. Measuring Motion Experimentally

Measure Your Walking Speed

Aim

To calculate walking speed over a measured distance.

Materials

  • measuring tape;
  • chalk;
  • stopwatch.

Procedure

  1. Mark a straight path of 20 m.
  2. One student stands at the starting point.
  3. Another student operates the stopwatch.
  4. Start timing when the walker begins moving.
  5. Stop timing when the walker crosses the finish mark.
  6. Record the time.
  7. Repeat the measurement three times.

Calculation

The distance is:

d=20 md=20\text{ m}d=20 m

If the measured time is t, then:

v=20tv=\frac{20}{t}v=t20​

Example

If the student takes 10 s:

v=2010v=\frac{20}{10}v=1020​v=2 m/sv=2\text{ m/s}v=2 m/s

Fair Test

For comparing students:

  • use the same distance;
  • use the same starting and finishing points;
  • measure time in the same way;
  • keep the path free from obstacles;
  • repeat measurements.

Exam Tip

A good experimental answer should clearly show:

Distance measured → Time measured → Formula used → Speed calculated

22. Reading Motion Data

Consider the following table.

| Time | Total Distance | | ---: | -------------: | | 0 s | 0 m | | 1 s | 4 m | | 2 s | 8 m | | 3 s | 12 m | | 4 s | 16 m |

During every one-second interval, the object covers 4 m.

Its speed is:

v=4 m1 sv=\frac{4\text{ m}}{1\text{ s}}v=1 s4 m​ v=4 m/sv=4\text{ m/s}v=4 m/s

The motion is uniform.

Now consider:

| Time | Total Distance | | ---: | -------------: | | 0 s | 0 m | | 1 s | 2 m | | 2 s | 5 m | | 3 s | 9 m | | 4 s | 14 m |

The distances covered during successive one-second intervals are:

  • 2 m;
  • 3 m;
  • 4 m;
  • 5 m.

These are unequal.

Therefore, the motion is non-uniform.

How to Detect Uniform Motion from a Table

Do not compare only total distances.

Find the distance covered during equal successive time intervals.

If those distances are equal:

Uniform motion

If they are unequal:

Non-uniform motion

23. Distance-Time Representation

Motion information can also be represented graphically.

A distance-time graph commonly shows:

  • time along the horizontal axis;
  • distance along the vertical axis.

For uniform motion, distance increases by equal amounts during equal intervals of time.

This produces a straight rising line.

Simple distance-time graph for uniform motion showing a straight rising line as distance increases uniformly with time
For uniform motion, distance increases at a constant rate with time.

Foundation Extension: Steeper Graph and Speed

For two objects showing uniform motion on the same distance-time scale:

  • both graphs may be straight lines;
  • the steeper line represents the object with greater speed.

Why?

A faster object covers more distance during the same time interval.

Detailed graph analysis is studied further in higher classes.

24. Everyday Applications of Speed

Speed is important in many situations.

Road Safety

A faster-moving vehicle generally requires a greater distance to stop safely.

Drivers therefore need:

  • appropriate speed;
  • sufficient distance from the vehicle ahead;
  • attention to road conditions.

Sports

Speed measurements help compare:

  • runners;
  • swimmers;
  • cyclists;
  • racing vehicles.

Transport

Speed helps estimate:

  • journey duration;
  • arrival time;
  • transport efficiency.

Science

Scientists measure the motion of:

  • animals;
  • machines;
  • water;
  • air;
  • celestial bodies.
Faster Is Not Always Better

Safe motion depends on the situation.

On crowded roads, sharp turns, slippery surfaces or near schools, a lower speed may be much safer.

Science helps us measure speed. Responsible behaviour helps us choose an appropriate speed.

25. A Complete Motion Problem Strategy

When solving numerical questions involving motion, follow these steps.

Step 1 — Identify the known quantities

Look for:

  • distance;
  • time;
  • speed.

Step 2 — Choose the correct formula

For speed:

v=dtv=\frac{d}{t}v=td​

For distance:

d=vtd=vtd=vt

For time:

t=dvt=\frac{d}{v}t=vd​

Step 3 — Check units

Make sure the units are compatible.

Step 4 — Substitute values

Insert the known values carefully.

Step 5 — Calculate

Show the mathematical step.

Step 6 — Write the final answer with unit

Common Mistake

Mistake: Substituting numbers immediately without writing the formula.

Correct idea: For school and foundation questions, show:

Given → Formula → Substitution → Calculation → Final answer with unit

This makes the solution easier to understand and reduces mistakes.

Complete Motion Calculation
Question
A scooter covers 360 metres in 30 seconds. Calculate its speed.
Solution

Given

d=360 md=360\text{ m}d=360 mt=30 st=30\text{ s}t=30 s

Formula

v=dtv=\frac{d}{t}v=td​

Substitution

v=36030v=\frac{360}{30}v=30360​

Calculation

v=12 m/sv=12\text{ m/s}v=12 m/s

Therefore:

v=12 m/s\boxed{v=12\text{ m/s}}v=12 m/s​

26. Concept Map

Concept Map

Measurement of Time and Motion→→Time
Measurement of Time and Motion→→Motion
Time→measured using→Clocks and Stopwatches
Time→investigated using→Simple Pendulum
Motion→described using→Distance
Motion→described using→Speed
Speed→constant in→Uniform Motion
Speed→changes in→Non-uniform Motion

Formula Revision

Formula / Key Relations

Speed

v=dtv=\frac{d}{t}v=td​

where:

  • v = speed;
  • d = distance travelled;
  • t = time taken.

SI unit:

m/s\text{m/s}m/s

Distance

d=vtd=vtd=vt

Use this relation when speed and time are known.

Time

t=dvt=\frac{d}{v}t=vd​

Use this relation when distance and speed are known.

Time Period of a Pendulum

T=tNT=\frac{t}{N}T=Nt​

where:

  • T = time period;
  • t = total measured time;
  • N = number of oscillations.

Basic Time Conversion

1 min=60 s1\text{ min}=60\text{ s}1 min=60 s1 h=60 min=3600 s1\text{ h}=60\text{ min}=3600\text{ s}1 h=60 min=3600 s

Average Speed

vavg=Total distanceTotal timev_{\text{avg}}=\frac{\text{Total distance}}{\text{Total time}}vavg​=Total timeTotal distance​

Exam Focus

Important Exam Areas

  • importance of time measurement;
  • traditional methods of measuring time;
  • sundial, water clock and sand clock;
  • modern clocks and stopwatches;
  • SI unit of time;
  • conversion of minutes, hours and seconds;
  • periodic motion;
  • simple pendulum;
  • bob, mean position and extreme positions;
  • meaning of one oscillation;
  • time period of a pendulum;
  • calculation of time period;
  • definition of motion;
  • importance of a reference point;
  • linear motion;
  • definition of speed;
  • speed, distance and time calculations;
  • SI unit of speed;
  • speedometer and odometer;
  • uniform linear motion;
  • non-uniform linear motion;
  • interpretation of motion tables;
  • simple distance-time representations;
  • average speed;
  • applications of speed in everyday life.

Exam Tip

For numerical questions, always write:

  1. Given
  2. Formula
  3. Substitution
  4. Calculation
  5. Final answer with unit

Do not write only the numerical value.

Key Terms

Key Terms

TimeSecondStopwatchSundialPeriodic MotionSimple PendulumBobMean PositionExtreme PositionOscillationTime PeriodMotionReference PointLinear MotionDistanceSpeedSpeedometerOdometerUniform Linear MotionNon-uniform Linear MotionAverage Speed

Quick Revision

Quick Revision

  • Time measurement is important in science, sports, transport and daily life.
  • Early methods of measuring time used repeating natural events.
  • Sundials use shadows produced by sunlight.
  • Water clocks and sand clocks use controlled movement of materials.
  • Modern clocks and stopwatches provide more convenient measurement.
  • The SI unit of time is the second (s).
  • One minute equals 60 seconds.
  • One hour equals 60 minutes or 3600 seconds.
  • Periodic motion repeats after equal intervals of time.
  • A simple pendulum consists of a bob suspended by a string from a fixed support.
  • One complete to-and-fro motion is one oscillation.
  • The time taken for one complete oscillation is the time period.
  • The time period can be found from total time divided by number of oscillations.
  • Measuring several oscillations improves the reliability of pendulum timing.
  • Motion means change of position with time relative to a reference point.
  • Linear motion occurs along a straight path.
  • Speed tells us the distance travelled per unit time.
  • The SI unit of speed is metre per second.
  • Distance can be calculated from speed multiplied by time.
  • Time can be calculated from distance divided by speed.
  • A speedometer measures speed.
  • An odometer records distance travelled.
  • Uniform linear motion covers equal distances in equal intervals of time.
  • Non-uniform linear motion covers unequal distances in equal intervals of time.
  • Average speed is total distance divided by total time.
  • All numerical answers involving physical quantities should include appropriate units.

Practice Questions

A. Multiple Choice Questions

Q1MCQEasyClass 7

The SI unit of time is:

A. minute B. hour C. second D. day

View Solution

Correct Answer: C. second

The second, written as s, is the SI unit of time.

Q2MCQEasyClass 7

Which device is most suitable for timing a 100-metre race?

A. Ruler B. Stopwatch C. Odometer D. Thermometer

View Solution

Correct Answer: B. Stopwatch

A stopwatch is designed to measure short time intervals accurately.

Q3MCQEasyClass 7

The time taken by a pendulum to complete one oscillation is called:

A. speed B. distance C. time period D. path length

View Solution

Correct Answer: C. time period

The time period is the time required for one complete oscillation.

Q4MCQModerateClass 7

A pendulum completes 10 oscillations in 20 seconds. Its time period is:

A. 0.5 s B. 2 s C. 10 s D. 20 s

View Solution

Using:

T=tNT=\frac{t}{N}T=Nt​

we get:

T=2010T=\frac{20}{10}T=1020​T=2 sT=2\text{ s}T=2 s

Correct Answer: B. 2 s

Q5MCQEasyClass 7

Speed is equal to:

A. distance × time B. distance ÷ time C. time ÷ distance D. distance + time

View Solution

Correct Answer: B. distance ÷ time

v=dtv=\frac{d}{t}v=td​
Q6MCQModerateClass 7

A runner travels 80 m in 10 s. The speed is:

A. 8 m/s B. 80 m/s C. 800 m/s D. 0.8 m/s

View Solution
v=8010v=\frac{80}{10}v=1080​v=8 m/sv=8\text{ m/s}v=8 m/s

Correct Answer: A. 8 m/s

Q7MCQModerateClass 7

A vehicle covers equal distances in equal intervals of time along a straight road. Its motion is:

A. non-uniform linear motion B. uniform linear motion C. random motion D. oscillatory motion

View Solution

Correct Answer: B. uniform linear motion

Equal distances are covered in equal intervals of time.

Q8MCQModerateClass 7

Which instrument records the distance travelled by a vehicle?

A. Speedometer B. Odometer C. Stopwatch D. Sundial

View Solution

Correct Answer: B. Odometer

An odometer records the distance travelled by a vehicle.

B. Very Short Answer Questions

  1. What is the SI unit of time?
  2. Define one oscillation of a pendulum.
  3. What is the time period of a pendulum?
  4. Write the formula for speed.
  5. State the SI unit of speed.
  6. What does a speedometer measure?
  7. What does an odometer measure?
  8. Define linear motion.
  9. What is uniform linear motion?
  10. What is non-uniform linear motion?

Answers

  1. Second, written as s.

  2. One complete to-and-fro motion of a pendulum is one oscillation.

  3. The time taken for one complete oscillation is called the time period.

v=dtv=\frac{d}{t}v=td​
  1. Metre per second, written as m/s.

  2. A speedometer measures speed.

  3. An odometer records distance travelled.

  4. Motion along a straight-line path is called linear motion.

  5. Uniform linear motion occurs when equal distances are covered in equal intervals of time along a straight path.

  6. Non-uniform linear motion occurs when unequal distances are covered in equal intervals of time along a straight path.

C. Short Answer Questions

Q9Short AnswerModerateClass 7

Why is it better to measure the time for 20 oscillations of a pendulum rather than only one?

View Solution

Starting and stopping a stopwatch exactly introduces a small reaction-time error.

If only one oscillation is timed, this error can affect the result significantly.

If several oscillations are timed, the time period can be calculated using:

T=tNT=\frac{t}{N}T=Nt​

This reduces the relative effect of the timing error.

Q10Short AnswerModerateClass 7

Distinguish between a speedometer and an odometer.

View Solution

A speedometer measures how fast a vehicle is moving.

An odometer records the total distance travelled by the vehicle.

Typical units are:

  • speedometer → km/h;
  • odometer → km.
Q11Short AnswerModerateClass 7

Explain why motion must be described relative to a reference point.

View Solution

An object's position can be different relative to different surroundings.

For example, a passenger sitting in a moving bus is:

  • at rest relative to the seat;
  • moving relative to a roadside tree.

Therefore, whether an object is moving depends on the chosen reference point.

Q12Short AnswerModerateClass 7

Differentiate between uniform and non-uniform linear motion.

View Solution

Uniform Linear Motion

The object moves along a straight path and covers equal distances in equal intervals of time.

Its speed remains constant.

Non-uniform Linear Motion

The object moves along a straight path but covers unequal distances in equal intervals of time.

Its speed changes.

D. Numerical Questions

Q13NumericalModerateClass 7

A cyclist covers 300 metres in 60 seconds. Calculate the speed.

View Solution

Given

d=300 md=300\text{ m}d=300 mt=60 st=60\text{ s}t=60 s

Formula

v=dtv=\frac{d}{t}v=td​

Substitution

v=30060v=\frac{300}{60}v=60300​

Calculation

v=5 m/sv=5\text{ m/s}v=5 m/s

Therefore:

5 m/s\boxed{5\text{ m/s}}5 m/s​
Q14NumericalModerateClass 7

A car moves at 12 m/s for 25 seconds. Calculate the distance travelled.

View Solution

Given

v=12 m/sv=12\text{ m/s}v=12 m/st=25 st=25\text{ s}t=25 s

Formula

d=vtd=vtd=vt

Substitution

d=12×25d=12\times25d=12×25

Calculation

d=300 md=300\text{ m}d=300 m

Therefore:

300 m\boxed{300\text{ m}}300 m​
Q15NumericalModerateClass 7

A runner covers 400 metres at a speed of 8 m/s. Find the time taken.

View Solution

Given

d=400 md=400\text{ m}d=400 mv=8 m/sv=8\text{ m/s}v=8 m/s

Formula

t=dvt=\frac{d}{v}t=vd​

Substitution

t=4008t=\frac{400}{8}t=8400​

Calculation

t=50 st=50\text{ s}t=50 s

Therefore:

50 s\boxed{50\text{ s}}50 s​
Q16NumericalModerateClass 7

A pendulum completes 25 oscillations in 50 seconds. Find its time period.

View Solution

Given

N=25N=25N=25t=50 st=50\text{ s}t=50 s

Formula

T=tNT=\frac{t}{N}T=Nt​

Substitution

T=5025T=\frac{50}{25}T=2550​

Calculation

T=2 sT=2\text{ s}T=2 s

Therefore:

2 s\boxed{2\text{ s}}2 s​

E. Application and HOTS Questions

Q17ApplicationHardClass 7 Foundation

Runner A covers 100 m in 20 s. Runner B covers 120 m in 24 s. Which runner is faster?

View Solution

Runner A

vA=10020=5 m/sv_A=\frac{100}{20}=5\text{ m/s}vA​=20100​=5 m/s

Runner B

vB=12024=5 m/sv_B=\frac{120}{24}=5\text{ m/s}vB​=24120​=5 m/s

Therefore:

vA=vB=5 m/s\boxed{v_A=v_B=5\text{ m/s}}vA​=vB​=5 m/s​

Both runners have the same speed.

Q18HOTSHardClass 7 Foundation

A bus travels 20 m during the first 5 seconds, 30 m during the next 5 seconds and 40 m during the next 5 seconds. Is its motion uniform? Explain.

View Solution

The time intervals are equal:

  • 5 s;
  • 5 s;
  • 5 s.

But the distances are:

  • 20 m;
  • 30 m;
  • 40 m.

These distances are unequal.

Therefore:

The bus is showing non-uniform motion.

Its speed is changing.

Q19ApplicationHardClass 7 Foundation

A passenger is sitting still inside a train moving at constant speed. Is the passenger at rest or in motion?

View Solution

The answer depends on the reference point.

Relative to the train seat, the passenger is at rest.

Relative to a person standing beside the railway track, the passenger is in motion.

Therefore, motion is relative to a chosen reference point.

Q20HOTSHardClass 7 Foundation

Two cars travel for exactly 10 seconds. Car A covers 150 m and Car B covers 120 m. Which car is faster, and why?

View Solution

Car A

vA=15010=15 m/sv_A=\frac{150}{10}=15\text{ m/s}vA​=10150​=15 m/s

Car B

vB=12010=12 m/sv_B=\frac{120}{10}=12\text{ m/s}vB​=10120​=12 m/s

Since:

15 m/s>12 m/s15\text{ m/s}>12\text{ m/s}15 m/s>12 m/s

Car A is faster because it covers a greater distance in the same amount of time.

Q21ApplicationHardClass 7 Foundation

Why is recording the time for many pendulum oscillations scientifically better than recording only one oscillation?

View Solution

Human reaction time makes it difficult to start and stop a stopwatch at exactly the correct instant.

For one oscillation, even a small timing error can significantly affect the result.

When many oscillations are timed:

T=Total timeNumber of oscillationsT=\frac{\text{Total time}}{\text{Number of oscillations}}T=Number of oscillationsTotal time​

the effect of small timing errors is reduced.

Repeated trials can improve reliability further.

Assertion–Reason

Q22Assertion-ReasonModerateClass 7

Assertion: A faster object covers more distance than a slower object in the same amount of time.

Reason: Speed is distance travelled per unit time.

Choose the correct option:

A. Both Assertion and Reason are true, and Reason correctly explains Assertion. B. Both are true, but Reason does not explain Assertion. C. Assertion is true, but Reason is false. D. Both are false.

View Solution

Correct Answer: A

Speed tells us how much distance an object travels per unit time.

Therefore, for the same time interval, a faster object covers a greater distance.

Q23Assertion-ReasonModerateClass 7

Assertion: An object in uniform linear motion covers equal distances in equal intervals of time.

Reason: Its speed remains constant.

Choose the correct option:

A. Both Assertion and Reason are true, and Reason correctly explains Assertion. B. Both are true, but Reason does not explain Assertion. C. Assertion is true, but Reason is false. D. Both are false.

View Solution

Correct Answer: A

Constant speed means that equal distances are covered in equal time intervals.

Q24Assertion-ReasonModerateClass 7

Assertion: One complete oscillation of a pendulum is motion from one extreme position to the other extreme position only.

Reason: A complete oscillation requires the bob to return to its starting extreme position.

Choose the correct option:

A. Both are true. B. Assertion is true, but Reason is false. C. Assertion is false, but Reason is true. D. Both are false.

View Solution

Correct Answer: C

Moving from one extreme position to the other is only half of a complete oscillation.

The bob must return to the starting extreme position to complete one oscillation.

Apply Your Learning

Choose a safe straight path at school or home.

Mark a distance of 10 m.

Ask three participants to walk the same distance while another person measures their times.

Create a table:

| Participant | Distance | Time | Speed | | ----------- | -------: | ---: | ----: | | A | 10 m | ... | ... | | B | 10 m | ... | ... | | C | 10 m | ... | ... |

For each participant, calculate speed using:

v=dtv=\frac{d}{t}v=td​

Since the distance is 10 m:

v=10tv=\frac{10}{t}v=t10​

Then answer:

  1. Who had the greatest speed?
  2. Who took the least time?
  3. When everyone covers the same distance, does the fastest participant take the least time?
  4. Why should each measurement be repeated?
  5. What factors could cause measurement error?

Think Like a Physicist

For every motion problem, identify what you know:

  • distance;
  • time;
  • speed.

Then choose the correct relation.

Speed

v=dtv=\frac{d}{t}v=td​

Distance

d=vtd=vtd=vt

Time

t=dvt=\frac{d}{v}t=vd​

Finally, check the unit.

Common Mistakes to Avoid

Common Mistake

Mistake: Writing only 5 as the final answer to a speed question.

Correct idea: A speed requires a unit.

For example:

5 m/s\boxed{5\text{ m/s}}5 m/s​

Common Mistake

Mistake: Speed is calculated as time divided by distance.

Correct idea:

v=dt\boxed{v=\frac{d}{t}}v=td​​

Common Mistake

Mistake: A pendulum moving from one extreme position to the other completes one oscillation.

Correct idea: It must return to the starting extreme position to complete one oscillation.

Common Mistake

Mistake: An object covering more total distance must always be faster.

Correct idea: Speed depends on both distance and time.

Common Mistake

Mistake: An odometer measures speed.

Correct idea: A speedometer measures speed, while an odometer records distance travelled.

Common Mistake

Mistake: Equal total distances automatically mean uniform motion.

Correct idea: For uniform motion, equal distances must be covered in equal successive time intervals.

Final Chapter Summary

Chapter Summary

  • Accurate measurement of time is important in science, sports, transport and everyday life.
  • Natural cycles and devices such as sundials, water clocks and sand clocks were used historically to measure time.
  • Modern clocks and stopwatches provide convenient measurement of time intervals.
  • The SI unit of time is the second (s).
  • A simple pendulum consists of a bob suspended from a fixed support by a string.
  • One complete to-and-fro motion of a pendulum is called one oscillation.
  • The time taken for one oscillation is called the time period.
  • The time period can be calculated by dividing the total measured time by the number of oscillations.
  • Measuring several oscillations improves the reliability of pendulum timing.
  • An object is in motion when its position changes with time relative to a reference point.
  • Linear motion occurs along a straight path.
  • Speed is the distance travelled per unit time.
  • The SI unit of speed is metre per second.
  • Distance can be calculated using speed multiplied by time.
  • Time can be calculated using distance divided by speed.
  • A speedometer measures speed, while an odometer records distance travelled.
  • Uniform linear motion covers equal distances in equal intervals of time.
  • Non-uniform linear motion covers unequal distances in equal intervals of time.
  • Average speed is found by dividing total distance by total time.
  • Tables and graphs can help us identify patterns of motion.
  • Numerical answers involving physical quantities should always include appropriate units.
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