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CBSE NCERT Chapter Notes

Connecting the Dots

Class 7 Mathematics, Chapter 13

By Preksha InstitutePublished: 19 August 202628 min readMedium📋 Exam Relevant
Mathematics chapters13 of 15
  1. 01Large Numbers Around Us
  2. 02Arithmetic Expressions
  3. 03A Peek Beyond the Point
  4. 04Expressions Using Letter-Numbers
  5. 05Parallel and Intersecting Lines
  6. 06Number Play
  7. 07A Tale of Three Intersecting Lines
  8. 08Working with Fractions
  9. 09Geometric Twins
  10. 10Operations with Integers
  11. 11Finding Common Ground
  12. 12Another Peek Beyond the Point
  13. 13Connecting the Dots
  14. 14Constructions and Tilings
  15. 15Finding the Unknown
Class 7

Mathematics

Chapter 13 of 15

  1. 01Large Numbers Around Us
  2. 02Arithmetic Expressions
  3. 03A Peek Beyond the Point
  4. 04Expressions Using Letter-Numbers
  5. 05Parallel and Intersecting Lines
  6. 06Number Play
  7. 07A Tale of Three Intersecting Lines
  8. 08Working with Fractions
  9. 09Geometric Twins
  10. 10Operations with Integers
  11. 11Finding Common Ground
  12. 12Another Peek Beyond the Point
  13. 13Connecting the Dots
  14. 14Constructions and Tilings
  15. 15Finding the Unknown
View subject overview
Home›Resources›class 7›mathematics›connecting the dots
Quick Links:Resources HomeBack to Class 7View all chapters
Class 7MathematicsChapter 13NCERT • Ganita Prakash

Connecting the Dots

Learn how data can answer questions using averages, median, range, dot plots and bar graphs.

Chapter Snapshot

  • Statistics begins with meaningful questions and data.
  • Mean and median describe representative values.
  • Range describes how spread out data is.
  • Outliers can strongly affect the mean.
  • Graphs help us compare and interpret data.

What You Will Learn

  • ✓Recognise questions that can be answered using data
  • ✓Calculate and interpret the arithmetic mean
  • ✓Find and interpret the median
  • ✓Identify outliers and understand their effect on data
  • ✓Use range to describe spread
  • ✓Read and construct simple dot plots
  • ✓Read and compare clustered bar graphs
  • ✓Choose suitable summaries and representations for a data set
Exam PriorityBoardsVery HighFoundationHigh

Chapter Overview

Statistics helps us collect, organise and interpret data.

A good statistical question expects variation in its answers.

For example:

How many minutes do students in our class take to reach school?

Different students may give different answers, so data is needed.

1. Statistical Questions

Statistical Question

A statistical question is answered by collecting data and expects variation in the data.

Examples:

  • How tall are the students in Class 7?
  • How many books did students read last month?
  • How much time do students spend travelling to school?

A question such as “How old am I?” is not statistical because it asks for one fixed answer.

2. Arithmetic Mean

The arithmetic mean is a commonly used representative value.

Arithmetic Mean

Mean=Sum of all observationsNumber of observations\text{Mean} = \frac{\text{Sum of all observations}}{\text{Number of observations}}Mean=Number of observationsSum of all observations​
Find the Mean
Question
Find the mean of 6, 8, 10, 12 and 14.
Solution
6+8+10+12+14=506+8+10+12+14=506+8+10+12+14=50

There are 5 observations.

Mean=505=10\text{Mean}=\frac{50}{5}=\boxed{10}Mean=550​=10​

3. Median

Median

The median is the middle value when data is arranged in order.

For an odd number of observations:

3, 5, 7, 9, 113,\ 5,\ 7,\ 9,\ 113, 5, 7, 9, 11

the median is:

7\boxed{7}7​

For an even number of observations, take the mean of the two middle values.

Even Number of Values

For:

2, 4, 8, 102,\ 4,\ 8,\ 102, 4, 8, 10

the middle values are 4 and 8.

Median=4+82=6\text{Median}=\frac{4+8}{2}=6Median=24+8​=6

4. Outliers

Outlier

An outlier is a value that is unusually far from most of the other data values.

Consider:

10, 11, 12, 12, 13, 5010,\ 11,\ 12,\ 12,\ 13,\ 5010, 11, 12, 12, 13, 50

The value 50 is an outlier.

Mean vs Median

An outlier can pull the mean strongly up or down.

The median is often less affected by an extreme value.

5. Spread and Range

Range

The range measures the spread from the smallest to the largest observation.

Range=Maximum−Minimum\text{Range} = \text{Maximum} - \text{Minimum}Range=Maximum−Minimum

For:

4, 7, 9, 12, 154,\ 7,\ 9,\ 12,\ 154, 7, 9, 12, 15 Range=15−4=11\text{Range}=15-4=\boxed{11}Range=15−4=11​

6. Dot Plots

A dot plot places one dot for each observation above its value.

It helps us see:

  • common values;
  • clusters;
  • gaps;
  • unusual values;
  • overall spread.

Read Before You Calculate

A graph often shows the shape of data more clearly than a single average.

Always look at the distribution as well as the mean or median.

7. Clustered Bar Graphs

Clustered bar graphs place related bars side by side.

They are useful for comparing categories such as:

  • boys and girls;
  • two different years;
  • two teams;
  • different classes.

Exam Tip · Class 7

When reading a graph, first check:

  1. title;
  2. labels;
  3. scale;
  4. units;
  5. what each bar or dot represents.

8. What Makes a Question Statistical?

A statistical question expects variation in the answers and is answered by collecting data.

For example, “How tall are the students in Class 7?” is statistical because students have different heights. “How tall is this particular desk?” is not statistical in the same way because it asks for one fixed measurement.

Think About Variation

Before collecting data, ask: Do I expect different answers? If yes, the question is likely statistical.

9. Mean and Median Tell Different Stories

The mean uses every value. The median depends on the middle position after arranging the data.

Consider:

4, 5, 5, 6, 204,\ 5,\ 5,\ 6,\ 204, 5, 5, 6, 20

The median is 5. The mean is:

4+5+5+6+205=8\frac{4+5+5+6+20}{5}=854+5+5+6+20​=8

The value 20 pulls the mean upward. This shows why an outlier can affect the mean much more than the median.

Always Order Data Before Finding Median

Median is based on position. Arrange the data from smallest to largest before identifying the middle value or middle pair.

10. Range and Spread

Range gives a simple measure of how spread out a data set is.

Range=maximum−minimum\text{Range}=\text{maximum}-\text{minimum}Range=maximum−minimum

If scores are 12,15,16,17,2012,15,16,17,2012,15,16,17,20, then:

20−12=820-12=820−12=8

A larger range usually indicates greater spread, but it depends only on the two extreme values.

11. Reading Dot Plots

A dot plot places one dot for each observation above its value. It allows us to see:

  • the most common values;
  • clusters;
  • gaps;
  • unusual values;
  • overall spread.

When reading a dot plot, count dots carefully. Several dots may be stacked above the same value.

12. Clustered Bar Graphs

Clustered bar graphs compare two or more categories for each group. Always read:

  1. the graph title;
  2. horizontal-axis labels;
  3. vertical-axis scale;
  4. legend or key;
  5. units.
Comparing Data
Question
Class A has scores 12, 14, 14, 15, 15. Class B has 5, 14, 14, 15, 22. Which class has the more stable scores?
Solution

Class A range:

15−12=315-12=315−12=3

Class B range:

22−5=1722-5=1722−5=17

Class A has much less spread, so its scores are more stable.

13. Choosing a Useful Summary

There is no single statistic that tells everything about a data set. Mean is useful when values are reasonably balanced. Median is often more representative when extreme values are present. Range gives a quick sense of spread.

Exam Tip · Class 7

When interpreting data, do not report only a calculation. Write what the number means in the context of the question.

14. Complete Data-handling Notes

Organising Raw Data

Raw data can be difficult to read. Sort values or organise them into a table before finding summaries. Ordered data makes the median, minimum, maximum and range easier to identify.

Example data:

12,9,15,9,11,14,912,9,15,9,11,14,912,9,15,9,11,14,9

Ordered:

9,9,9,11,12,14,159,9,9,11,12,14,159,9,9,11,12,14,15

Now the median is immediately visible as 11.

Mean

The arithmetic mean is:

Mean=sum of observationsnumber of observations\text{Mean}=\frac{\text{sum of observations}}{\text{number of observations}}Mean=number of observationssum of observations​

For 6,8,9,12,156,8,9,12,156,8,9,12,15:

Mean=505=10\text{Mean}=\frac{50}{5}=10Mean=550​=10

The mean need not be one of the original observations.

Median with Even Number of Values

If there are an even number of observations, take the mean of the two middle values after ordering.

For:

3,5,8,123,5,8,123,5,8,12

median is:

5+82=6.5\frac{5+8}{2}=6.525+8​=6.5

Outliers

An outlier is a value noticeably far from most of the data. It can affect the mean and range strongly.

Consider:

10,11,11,12,5610,11,11,12,5610,11,11,12,56

The value 56 is an outlier. The median is 11, but the mean is much higher because of 56.

Dot Plot Interpretation

A dot plot preserves every data value. Look for:

  • where most dots cluster;
  • the most frequent values;
  • empty gaps;
  • possible outliers;
  • overall range.

If the dots are tightly grouped, the data has less spread than a plot with dots scattered over a wider interval.

Bar-graph Scale

A bar graph can be misread if the vertical scale is ignored. Check whether marks increase by 1, 5, 10 or another amount. Also check whether the axis begins at zero.

Data Needs Context

A graph or average without units and labels can be misleading. Always state what the values represent.

Comparing Two Data Sets

Do not compare only the mean. Two classes can have the same mean but very different spread.

Example:

Class A: 9,10,10,10,119,10,10,10,119,10,10,10,11

Class B: 2,6,10,14,182,6,10,14,182,6,10,14,18

Both have mean 10, but Class A is tightly clustered while Class B is much more spread out.

Quick Check
Can two data sets have the same mean but different ranges?
Show answer
Yes. Mean describes centre, while range describes spread.

15. More Data Examples

Mean and Median
Question
For the data 4, 6, 7, 7, 11, find the mean and median.
Solution

The data is already ordered.

Median is the middle value:

7\boxed{7}7​

Mean:

4+6+7+7+115=355=7\frac{4+6+7+7+11}{5}=\frac{35}{5}=\boxed{7}54+6+7+7+11​=535​=7​

Here the mean and median happen to be equal.

When an Outlier Appears

Now change 11 to 31:

4,6,7,7,314,6,7,7,314,6,7,7,31

Median remains 7, but mean becomes:

555=11\frac{55}{5}=11555​=11

The single large value changes the mean strongly. This is why a data summary must be interpreted, not merely calculated.

Reading a Graph Carefully

When comparing bars, use the numerical scale rather than visual height alone. If the axis starts at 50 rather than 0, small numerical differences may look exaggerated.

Asking Good Data Questions

A useful statistical investigation clearly identifies:

  • what is being measured;
  • who or what is included;
  • the units;
  • how data will be recorded;
  • what comparison or summary is needed.
Quick Check
Which is more affected by one very large outlier: mean or median?
Show answer
The mean is usually affected more strongly.

Common Mistakes

Common Mistake

Do not calculate the median before arranging data in order.

Common Mistake

Mean and median are not always equal. They answer the idea of a “typical value” in different ways.

Quick Revision

Quick Revision

  • Statistical questions expect variation.
  • Mean = total ÷ number of observations.
  • Median = middle ordered value.
  • For even data counts, median is the mean of two middle values.
  • Range = maximum − minimum.
  • Outliers can affect the mean strongly.
  • Dot plots show distribution.
  • Clustered bar graphs help compare groups.

Practice Questions

Q1NumericalEasyClass 7

Find the mean of:

4, 6, 8, 10, 124,\ 6,\ 8,\ 10,\ 124, 6, 8, 10, 12
View Solution
4+6+8+10+125=405=8\frac{4+6+8+10+12}{5} = \frac{40}{5} = \boxed{8}54+6+8+10+12​=540​=8​
Q2NumericalEasyClass 7

Find the median of:

3, 8, 5, 11, 63,\ 8,\ 5,\ 11,\ 63, 8, 5, 11, 6
View Solution

Arrange:

3, 5, 6, 8, 113,\ 5,\ 6,\ 8,\ 113, 5, 6, 8, 11

Median:

6\boxed{6}6​
Q3NumericalModerateClass 7

Find the range of:

14, 18, 9, 21, 1214,\ 18,\ 9,\ 21,\ 1214, 18, 9, 21, 12
View Solution

Maximum = 21, minimum = 9.

21−9=1221-9=\boxed{12}21−9=12​
Q4Short AnswerModerateFoundation

Why might the median be more useful than the mean for the data 10,11,12,12,13,10010,11,12,12,13,10010,11,12,12,13,100?

View Solution

100 is an outlier and pulls the mean upward. The median remains close to the central cluster, so it may better describe a typical value.

Additional Practice

Q5NumericalEasyClass 7

Find the mean of 5, 7, 8 and 12.

View Solution
5+7+8+124=324=8\frac{5+7+8+12}{4}=\frac{32}{4}=\boxed{8}45+7+8+12​=432​=8​
Q6NumericalModerateClass 7

Find the median of 3, 9, 4, 8, 6.

View Solution
Arrange: 3, 4, 6, 8, 9. The middle value is 6\boxed{6}6​.
Q7NumericalModerateClass 7

Find the range of 11, 15, 19, 10, 23.

View Solution
23−10=1323-10=\boxed{13}23−10=13​
Q8Short AnswerHardFoundation

Why might the median be more useful than the mean for incomes in a group containing one extremely high income?

View Solution
The extremely high value can pull the mean upward strongly, while the median depends mainly on the middle position and is less affected by the outlier.

Chapter Summary

Chapter Summary

  • Statistics connects questions with data.
  • Mean and median describe central values.
  • Range measures spread.
  • Outliers may change the mean significantly.
  • Dot plots and clustered bar graphs reveal patterns and comparisons visually.
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