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CBSE NCERT Chapter Notes

Finding the Unknown

Class 7 Mathematics, Chapter 15

By Preksha InstitutePublished: 19 August 202628 min readMediumπŸ“‹ Exam Relevant
Mathematics chapters15 of 15
  1. 01Large Numbers Around Us
  2. 02Arithmetic Expressions
  3. 03A Peek Beyond the Point
  4. 04Expressions Using Letter-Numbers
  5. 05Parallel and Intersecting Lines
  6. 06Number Play
  7. 07A Tale of Three Intersecting Lines
  8. 08Working with Fractions
  9. 09Geometric Twins
  10. 10Operations with Integers
  11. 11Finding Common Ground
  12. 12Another Peek Beyond the Point
  13. 13Connecting the Dots
  14. 14Constructions and Tilings
  15. 15Finding the Unknown
Class 7

Mathematics

Chapter 15 of 15

  1. 01Large Numbers Around Us
  2. 02Arithmetic Expressions
  3. 03A Peek Beyond the Point
  4. 04Expressions Using Letter-Numbers
  5. 05Parallel and Intersecting Lines
  6. 06Number Play
  7. 07A Tale of Three Intersecting Lines
  8. 08Working with Fractions
  9. 09Geometric Twins
  10. 10Operations with Integers
  11. 11Finding Common Ground
  12. 12Another Peek Beyond the Point
  13. 13Connecting the Dots
  14. 14Constructions and Tilings
  15. 15Finding the Unknown
View subject overview
Homeβ€ΊResourcesβ€Ίclass 7β€Ίmathematicsβ€Ίfinding the unknown
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Class 7MathematicsChapter 15NCERT β€’ Ganita Prakash

Finding the Unknown

Learn how equations help us find unknown numbers using balance, inverse operations and systematic reasoning.

Chapter Snapshot

  • An equation states that two expressions are equal.
  • The unknown is represented by a letter.
  • Both sides of an equation must remain balanced.
  • Inverse operations help isolate the unknown.
  • A solution can be checked by substitution.

What You Will Learn

  • βœ“Understand equations and unknown quantities
  • βœ“Identify the left-hand side and right-hand side of an equation
  • βœ“Solve equations using the balance principle
  • βœ“Use inverse operations to isolate the unknown
  • βœ“Solve one-step and two-step equations
  • βœ“Solve simple equations with the unknown on both sides
  • βœ“Form equations from word problems
  • βœ“Check a solution by substituting it back into the original equation
Exam PriorityBoardsVery HighFoundationHigh

Chapter Overview

Suppose a box and 3 kg together weigh 11 kg.

If the box weighs xxx kg:

x+3=11x+3=11x+3=11

The number that makes this statement true is the unknown value.

Balance Idea

Think of an equation as a balanced scale.

Whatever operation you perform on one side must also be performed on the other side.

1. What Is an Equation?

Equation

An equation is a mathematical statement showing that two expressions are equal.

Example:

x+5=12x+5=12x+5=12

The left side is called the LHS and the right side is the RHS.

Parts of an Equation

PartMeaning
LHSExpression to the left of =
RHSExpression to the right of =
UnknownNumber represented by a letter
SolutionValue that makes LHS = RHS

2. Trial and Error

For:

x+4=10x+4=10x+4=10

try different values.

If x=5x=5x=5:

5+4=95+4=95+4=9

Not correct.

If x=6x=6x=6:

6+4=106+4=106+4=10

So:

x=6\boxed{x=6}x=6​

Trial and error is useful for simple equations, but a systematic method is faster.

3. Same Operation on Both Sides

Addition Equation
Question
Solve x + 7 = 15.
Solution

Subtract 7 from both sides:

x+7βˆ’7=15βˆ’7x+7-7=15-7x+7βˆ’7=15βˆ’7x=8\boxed{x=8}x=8​
Subtraction Equation
Question
Solve x - 5 = 12.
Solution

Add 5 to both sides:

xβˆ’5+5=12+5x-5+5=12+5xβˆ’5+5=12+5x=17\boxed{x=17}x=17​

4. Multiplication and Division Equations

Multiplication Equation
Question
Solve 4x = 28.
Solution

Divide both sides by 4:

4x4=284\frac{4x}{4}=\frac{28}{4}44x​=428​x=7\boxed{x=7}x=7​
Division Equation
Question
Solve x/5 = 9.
Solution

Multiply both sides by 5:

x=9Γ—5x=9\times5x=9Γ—5x=45\boxed{x=45}x=45​

5. Inverse Operations

Inverse Operations

OperationInverse
AdditionSubtraction
SubtractionAddition
MultiplicationDivision
DivisionMultiplication

Goal

The aim is to isolate the unknown while keeping the equation balanced.

6. Two-Step Equations

Two-Step Equation
Question
Solve 3x + 4 = 19.
Solution

Subtract 4 from both sides:

3x=153x=153x=15

Divide both sides by 3:

x=5x=5x=5

Therefore:

x=5\boxed{x=5}x=5​

7. Unknown on Both Sides

Unknown on Both Sides
Question
Solve 5x + 2 = 3x + 14.
Solution

Subtract 3x3x3x from both sides:

2x+2=142x+2=142x+2=14

Subtract 2:

2x=122x=122x=12

Divide by 2:

x=6\boxed{x=6}x=6​

8. Checking a Solution

Always substitute the answer back into the original equation.

For:

3x+4=193x+4=193x+4=19

and x=5x=5x=5:

3(5)+4=15+4=193(5)+4=15+4=193(5)+4=15+4=19

LHS = RHS, so the solution is correct.

Exam Tip Β· Class 7

A quick substitution check can catch sign and arithmetic mistakes.

9. Word Problems

Translate the situation into an equation.

Age Problem

Riya is 4 years older than Aman. Riya is 15 years old.

Let Aman's age be xxx.

x+4=15x+4=15x+4=15x=11x=11x=11

So Aman is 11 years old.

Number Problem

Three times a number plus 2 is 20.

Let the number be nnn.

3n+2=203n+2=203n+2=203n=183n=183n=18n=6n=6n=6

10. Expression vs Equation

An expression such as:

3x+53x+53x+5

has no equality sign. An equation states that two expressions are equal:

3x+5=203x+5=203x+5=20

The equation asks which value of xxx makes the equality true.

Expression and Equation

ExpressionEquation
3x + 53x + 5 = 20
No equality signContains =
Can be evaluated when x is knownCan be solved to find x

11. The Balance Principle

An equation behaves like a balanced scale. If the same operation is performed on both sides, equality is preserved.

If:

x+7=15x+7=15x+7=15

subtract 7 from both sides:

x+7βˆ’7=15βˆ’7x+7-7=15-7x+7βˆ’7=15βˆ’7

so:

x=8x=8x=8

Do the Same to Both Sides

You may add, subtract, multiply or divide both sides by the same suitable number. When dividing, that number must not be zero.

12. Solving Two-step Equations

Work backward through the operations around the unknown.

Two-step Equation
Question
Solve 4x + 3 = 27.
Solution

Subtract 3 from both sides:

4x=244x=244x=24

Divide both sides by 4:

x=6x=6x=6

Check:

4(6)+3=274(6)+3=274(6)+3=27

So:

x=6\boxed{x=6}x=6​

13. Unknown on Both Sides

When the unknown appears on both sides, collect letter terms on one side and number terms on the other.

Example:

5x+2=3x+145x+2=3x+145x+2=3x+14

Subtract 3x3x3x from both sides:

2x+2=142x+2=142x+2=14

Subtract 2:

2x=122x=122x=12

Therefore:

x=6x=6x=6

14. Forming Equations from Words

A word problem becomes easier when the unknown is named first.

Example: β€œThree times a number increased by 5 is 29.”

Let the number be xxx.

3x+5=293x+5=293x+5=29

Solve:

3x=243x=243x=24 x=8x=8x=8

Translate One Phrase at a Time

  • β€œfive more than xxx” β†’ x+5x+5x+5
  • β€œfive less than xxx” β†’ xβˆ’5x-5xβˆ’5
  • β€œthree times xxx” β†’ 3x3x3x
  • β€œhalf of xxx” β†’ x2\frac{x}{2}2x​

Do not reverse subtraction phrases accidentally.

15. Checking and Interpreting Solutions

A solution is not complete until it is checked in the original equation. Substitution verifies both the algebra and the arithmetic.

In a word problem, also check whether the answer makes sense. An equation may be solved correctly but the interpretation may still be wrong if units or context are ignored.

Exam Tip Β· Class 7

Show each balancing step on a new line. Avoid writing β€œmove 5 to the other side and change its sign” without understanding why; the reliable idea is to perform the same inverse operation on both sides.

16. Complete Equation Notes

Unknowns and Solutions

A letter such as xxx represents the value to be found. A solution is a value that makes the equation true.

For:

x+4=9x+4=9x+4=9

x=5x=5x=5 is a solution because:

5+4=95+4=95+4=9

But x=6x=6x=6 is not a solution because 6+4β‰ 96+4\ne96+4ξ€ =9.

One-step Equations

Use the inverse operation.

xβˆ’7=12x-7=12xβˆ’7=12

Add 7 to both sides:

x=19x=19x=19

For:

5x=405x=405x=40

divide both sides by 5:

x=8x=8x=8

For:

x6=7\frac{x}{6}=76x​=7

multiply both sides by 6:

x=42x=42x=42

Brackets in Equations

Sometimes simplify or expand before solving.

Example:

3(x+2)=213(x+2)=213(x+2)=21

Divide both sides by 3:

x+2=7x+2=7x+2=7

so:

x=5x=5x=5

Alternatively expand first:

3x+6=213x+6=213x+6=21

Both methods give the same result.

Equations with Unknown on Both Sides

Example:

7xβˆ’5=4x+167x-5=4x+167xβˆ’5=4x+16

Subtract 4x4x4x from both sides:

3xβˆ’5=163x-5=163xβˆ’5=16

Add 5:

3x=213x=213x=21

Therefore:

x=7x=7x=7

Word Problems Step by Step

  1. Choose a letter for the unknown.
  2. Translate the information into an equation.
  3. Solve using balanced operations.
  4. Check the solution.
  5. Write the answer with the correct unit or meaning.
Perimeter Equation

A rectangle has length 3 cm more than its breadth. Its perimeter is 30 cm. Let breadth be bbb cm, so length is (b+3)(b+3)(b+3) cm.

2b+2(b+3)=302b+2(b+3)=302b+2(b+3)=304b+6=304b+6=304b+6=304b=244b=244b=24b=6b=6b=6

Length is 9 cm.

Common Translation Phrases

  • a number increased by 8 β†’ x+8x+8x+8
  • 8 less than a number β†’ xβˆ’8x-8xβˆ’8
  • 8 less than twice a number β†’ 2xβˆ’82x-82xβˆ’8
  • three consecutive whole numbers β†’ x,x+1,x+2x,x+1,x+2x,x+1,x+2
  • twice a number is 14 β†’ 2x=142x=142x=14

Common Mistake

β€œ5 less than xxx” means xβˆ’5x-5xβˆ’5, not 5βˆ’x5-x5βˆ’x. Pay attention to the order of subtraction phrases.

Final Check

Always substitute the answer into the original equation. If the two sides are unequal, revisit your algebra or arithmetic.

Quick Check
Solve and check: 3x + 1 = 16.
Show answer
x = 5. Check: 3(5) + 1 = 16.

17. More Equation Practice Notes

Equation with Division
Question
Solve x/5 + 3 = 11.
Solution

Subtract 3 from both sides:

x5=8\frac{x}{5}=85x​=8

Multiply both sides by 5:

x=40x=40x=40

Therefore:

x=40\boxed{x=40}x=40​
Unknown on Both Sides
Question
Solve 6x - 7 = 4x + 9.
Solution

Subtract 4x4x4x from both sides:

2xβˆ’7=92x-7=92xβˆ’7=9

Add 7:

2x=162x=162x=16

Divide by 2:

x=8\boxed{x=8}x=8​

Equation-solving Checklist

Before finishing a solution, ask:

  1. Did I perform the same operation on both sides?
  2. Did I simplify correctly?
  3. Did I keep signs correct?
  4. Did I substitute the answer back into the original equation?
  5. In a word problem, did I answer what was actually asked?

Consecutive-number Problems

If one whole number is nnn, the next is n+1n+1n+1 and the next is n+2n+2n+2.

If three consecutive numbers have sum 45:

n+(n+1)+(n+2)=45n+(n+1)+(n+2)=45n+(n+1)+(n+2)=45 3n+3=453n+3=453n+3=45 3n=423n=423n=42 n=14n=14n=14

So the numbers are 14, 15 and 16.

Quick Check
If x = 7, does it solve 2x + 1 = 15?
Show answer
Yes, because 2(7) + 1 = 15.

Common Mistakes

Common Mistake

Do not change only one side of an equation. The equality must remain balanced.

Common Mistake

After solving, substitute the value into the original equation, not only the last step.

Quick Revision

Quick Revision

  • An equation shows equality between two expressions.
  • LHS is left of the equal sign; RHS is right.
  • A solution makes LHS equal RHS.
  • Do the same operation on both sides.
  • Use inverse operations to isolate the unknown.
  • Two-step equations are solved one operation at a time.
  • Unknowns can appear on both sides.
  • Always check by substitution.

Practice Questions

Q1NumericalEasyClass 7

Solve:

x+9=17x+9=17x+9=17
View Solution
x=17βˆ’9=8x=17-9=\boxed{8}x=17βˆ’9=8​
Q2NumericalEasyClass 7

Solve:

5x=355x=355x=35
View Solution
x=35Γ·5=7x=35\div5=\boxed{7}x=35Γ·5=7​
Q3NumericalModerateClass 7

Solve:

2x+5=192x+5=192x+5=19
View Solution
2x=142x=142x=14x=7x=\boxed{7}x=7​
Q4NumericalModerateFoundation

Solve:

4x+3=2x+154x+3=2x+154x+3=2x+15
View Solution
2x+3=152x+3=152x+3=152x=122x=122x=12x=6x=\boxed{6}x=6​

Apply Your Learning

Create an equation for each:

  1. A number increased by 8 is 21.
  2. Four times a number is 36.
  3. Twice a number plus 5 is 17.

Solve each equation and check your answer by substitution.

Additional Practice

Q5NumericalEasyClass 7

Solve x+9=17x+9=17x+9=17.

View Solution
Subtract 9 from both sides: x=8x=\boxed{8}x=8​.
Q6NumericalModerateClass 7

Solve 5xβˆ’4=315x-4=315xβˆ’4=31.

View Solution
5x=355x=355x=35, so x=7x=\boxed{7}x=7​.
Q7NumericalModerateClass 7

Solve 4x+3=2x+174x+3=2x+174x+3=2x+17.

View Solution
Subtract 2x2x2x: 2x+3=172x+3=172x+3=17. Then 2x=142x=142x=14, so x=7x=\boxed{7}x=7​.
Q8Short AnswerHardFoundation

A number doubled and then increased by 5 gives 31. Form and solve an equation.

View Solution
Let the number be xxx. Then 2x+5=312x+5=312x+5=31. So 2x=262x=262x=26 and x=13x=\boxed{13}x=13​.

Chapter Summary

Chapter Summary

  • Equations help find unknown quantities.
  • The equal sign means both sides have the same value.
  • Keeping both sides balanced is the key solving principle.
  • Inverse operations isolate the unknown.
  • Substitution verifies a solution.
  • Word problems become easier when translated into equations.
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